<?xml version="1.0"?>
<rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:dc="http://purl.org/dc/elements/1.1/"><rdf:Description rdf:about="https://repozitorij.uni-lj.si/IzpisGradiva.php?id=95862"><dc:title>Verifying time complexity of Turing machines</dc:title><dc:creator>Gajser,	David	(Avtor)
	</dc:creator><dc:creator>Cabello,	Sergio	(Mentor)
	</dc:creator><dc:creator>Mohar,	Bojan	(Komentor)
	</dc:creator><dc:subject>Turing machine</dc:subject><dc:subject>relativization</dc:subject><dc:subject>NP-completeness</dc:subject><dc:subject>crossing sequence</dc:subject><dc:subject>decidability</dc:subject><dc:subject>lower bound</dc:subject><dc:subject>time complexity</dc:subject><dc:subject>running time</dc:subject><dc:subject>linear time</dc:subject><dc:subject/><dc:description>The central problem in the dissertation is the following: "For a function ▫$T \colon \mathbb{N} \rightarrow \mathbb{R}_{\,\geq 0}$▫, how hard is it to verify whether a given Turing machine runs in time at most ▫$T(n)$▫? Is it even possible?" Our first main contibution is that, for all reasonable functions ▫$T(n) = \operatorname{o}(n\log n)$▫, it is possible to verify with an algorithm whether a given one-tape Turing machine runs in time at most ▫$T(n)$▫. This is a tight bound on the order of growth for the function ▫$T$▫ because we prove that, for ▫$T(n) = \Omega(n\log n)$▫ and ▫$T(n)\geq n+1$▫, there exists no algorithm that would verify whether a given one-tape Turing machine runs in time at most ▫$T(n)$▫. As opposed to one-tape Turing machines, we show that we can verify with an algorithm whether a given multi-tape Turing machine runs in time at most ▫$T(n)$▫ if and only if ▫$T(n_0) &lt; n_0+1$▫ for some ▫$n_0 \in \mathbb{N}$▫. Linear time bounds are the most natural algorithmically verifiable time bounds for one-tape Turing machines, because a one-tape Turing machine that runs in time ▫$\operatorname{o}(n\log n)$▫ actually runs in linear time. This motivates our second main contibution which is the analysis of complexity of the following family of problems, parameterized by integers ▫$C\geq 2$▫ and ▫$D \geq 1$▫: "Does a given one-tape ▫$q$▫-state Turing machine run in time ▫$Cn+D$▫?" Assuming a fixed tape and input alphabet, we show that these problems are co-NP-complete and we provide good lower bounds. Specifically, these problems cannot be solved in ▫$\operatorname{o}(q^{(C-1)/4})$▫ non-deterministic time by multi-tape Turing machines. We also show that the complements of these problems can be solved in ▫$\operatorname{O}(q^{C+2})$▫ non-deterministic time and not in ▫$\operatorname{o}(q^{(C-1)/4})$▫ non-deterministic time by multi-tape Turing machines. To prove the upper bound ▫$\operatorname{O}(q^{C+2})$▫, we use the so-called compactness theorem which is our third main contribution. We need more notation to state it in full generality, but a simple corollary tells the following: To verify whether an input one-tape Turing machine runs in time ▫$Cn+D$▫, it is enough to verify this on a finite number of inputs. We argue that our main results are proved with techniques that relativize and that using only such techniques we cannot solve the P versus NP problem.</dc:description><dc:publisher>[D. Gajser]</dc:publisher><dc:date>2015</dc:date><dc:date>2017-09-22 02:54:07</dc:date><dc:type>Doktorsko delo/naloga</dc:type><dc:identifier>95862</dc:identifier><dc:language>sl</dc:language></rdf:Description></rdf:RDF>
